flowchart LR O["🔭 Observable\nWhat we measure"] M["📐 Model\nWhat we assume"] I["💡 Inference\nWhat we derive"] O --> M --> I style O fill:#dbeafe,stroke:#2563eb style M fill:#fef3c7,stroke:#d97706 style I fill:#dcfce7,stroke:#16a34a
How far? The foundation of stellar astrophysics
February 12, 2026
By the end of this lecture, you will be able to:
Are all stars like our Sun?
Two stars appear equally bright in your telescope. What can you conclude?
A. They have the same luminosity
B. They are at the same distance
C. You can’t tell — brightness depends on both luminosity and distance
D. The brighter-looking one must be closer
Equal apparent brightness can mean:
Scenario 1: A luminous star far away
\[F = \frac{L_{\text{high}}}{4\pi d_{\text{far}}^2}\]
Scenario 2: A dim star nearby
\[F = \frac{L_{\text{low}}}{4\pi d_{\text{near}}^2}\]
The same flux \(F\) — completely different stars. Without distance, you’re stuck.
\[\text{Parallax} \xrightarrow{d = 1/p} \text{Distance} \xrightarrow{d + F} \text{Luminosity} \xrightarrow{L + T} \text{HR Diagram}\]
Everything starts with distance.
flowchart LR O["🔭 Observable\nWhat we measure"] M["📐 Model\nWhat we assume"] I["💡 Inference\nWhat we derive"] O --> M --> I style O fill:#dbeafe,stroke:#2563eb style M fill:#fef3c7,stroke:#d97706 style I fill:#dcfce7,stroke:#16a34a
| Step | This lecture |
|---|---|
| Observable | Position shifts, brightness |
| Model | Parallax geometry, ISL |
| Inference | Distance, luminosity |
Good scientists always ask: what am I assuming, and what would break it?
Angular Measure
The language of the sky
| Unit | Size |
|---|---|
| \(1^\circ\) | Full Moon width |
| \(1'\) (arcmin) | \(1/60\) of a degree |
| \(1''\) (arcsec) | \(1/3600\) of a degree |
Stellar parallax happens at the arcsecond scale — tiny shifts against distant background stars.
Definition: 1 radian is the angle subtended by an arc whose length equals the radius.
\[1 \text{ radian} = \frac{360^\circ}{2\pi} \approx 57.3^\circ\]
Radians are dimensionless: angle = arc length / radius = length / length.
Physics formulas like \(\sin\theta \approx \theta\) and \(v = r\omega\) only work in radians.
\[1 \text{ radian} = \frac{360 \times 3600''}{2\pi} \approx 206{,}265''\]
Inverted (the form you’ll use most):
\[\boxed{1'' = \frac{1}{206{,}265} \text{ rad} \approx 4.85 \times 10^{-6} \text{ rad}}\]
Memorize 206,265. It appears in every parallax calculation.
The Small-Angle Approximation
Connecting angular size, true size, and distance
For small angles (\(\alpha \ll 1\) rad):
\[\boxed{\alpha\,(\text{rad}) \approx \frac{s}{d}}\]
Physical meaning: Angular size is inversely proportional to distance.
The exact relation: \(\sin(\alpha/2) = R/d\)
For small \(\alpha\): \(\sin(\alpha/2) \approx \alpha/2\)
\[\implies \alpha \approx \frac{2R}{d} = \frac{s}{d}\]
How small is “small enough”?
At \(\alpha = 5°\), error is only 0.1%. For astronomy (arcseconds!), it’s essentially exact.
If you double your distance from an object (keeping its true size fixed), its angular size:
A. Doubles
B. Quadruples
C. Halves
D. Quarters
Given:
Convert: \(0.5^\circ = 1800'' \div 206{,}265 = 0.00873\) rad
Apply: \(s = \alpha \, d\)
\[s = (0.00873)(3.84 \times 10^{10} \text{ cm})\] \[\approx 3{,}350 \text{ km}\]
Actual lunar diameter: 3,474 km
Agreement within 4% — excellent!
. . .
The small-angle approximation works beautifully at half-degree scales.
Parallax
Distance from baseline geometry
Before we derive anything, explore the interactive demo:
Now let’s derive why this works. → Full-screen demo
As Earth orbits, a nearby star appears to shift against distant background stars.
The parallax angle \(p\) is defined as half the total shift, using a baseline of 1 AU (Earth’s orbital radius).
\[p\,(\text{rad}) \approx \frac{1\,\text{AU}}{d}\]
Convert parallax to arcseconds:
\[p\,('') = \frac{1\,\text{AU}}{d} \times 206{,}265\]
Define: 1 parsec (pc) = distance at which \(p = 1''\)
\[1\,\text{pc} = 206{,}265\,\text{AU} = 3.09 \times 10^{18}\,\text{cm} = 3.26\,\text{ly}\]
The distance formula becomes breathtakingly simple:
\[\boxed{d\,(\text{pc}) = \frac{1}{p\,('')}}\]
Star A has parallax \(p = 0.5''\). Star B has parallax \(p = 0.1''\).
A. Star A is closer (2 pc vs 10 pc)
B. Star B is closer (10 pc vs 2 pc)
C. They’re at the same distance
D. Can’t tell without knowing luminosity
Given: \(p = 0.768''\) (nearest star)
Step 1: Distance in parsecs \[d = \frac{1}{0.768} = 1.30\,\text{pc}\]
Step 2: Convert to centimeters \[d = 1.30 \times 3.09 \times 10^{18}\,\text{cm pc}^{-1}\] \[= 4.02 \times 10^{18}\,\text{cm}\]
Sanity check:
Nearby stars should be 1–5 pc. ✓
. . .
At 1.3 pc, Proxima is \(\sim 25\) trillion miles away — yet it’s the closest star.
This shows why parallax was historically so difficult to measure.
The nearest stellar neighborhood is a sparse place.
Most are red dwarfs too faint to see with the naked eye — the night sky is biased toward luminous stars.
| Mission | Precision | Stars | Distance reach |
|---|---|---|---|
| Ground (pre-1990) | \(\sim 50\) mas | \(\sim 1{,}000\) | \(\sim 20\) pc |
| Hipparcos (1989–93) | \(\sim 1\) mas | \(\sim 100{,}000\) | \(\sim 100\) pc |
| Gaia (2013–25) | \(\sim 10\) \(\mu\)as | \(\sim 1.8\) billion | \(\sim 10\) kpc |
Gaia’s \(100\times\) better precision directly translates to \(100\times\) better luminosity measurements for every star observed.
Problem: A star has parallax \(p = 0.050''\).
(a) What is its distance in parsecs?
(b) Convert to light-years.
(c) Could Hipparcos have measured this parallax? Could Gaia?
(d) Estimate the parallax of a star at the center of the Milky Way (\(\sim 8\) kpc away).
Reference: parallax geometry
Answers: (a) \(d = 1/0.050 = 20\) pc. (b) \(20 \times 3.26 = 65\) ly. (c) Yes (Hipparcos limit \(\sim 1\) mas \(= 0.001''\), this is much larger). (d) \(p = 1/8000 = 0.000125'' = 125\,\mu\)as — detectable by Gaia.
The Inverse-Square Law
How light spreads through space
If you move twice as far from a light source, by what factor does the brightness change?
Think about why before we derive it.
A star emits luminosity \(L\) uniformly in all directions.
At distance \(d\), this energy is spread over a sphere of area \(4\pi d^2\).
Flux = energy per time per area:
\[\boxed{F = \frac{L}{4\pi d^2}}\]
Double the distance → flux drops by 4×. Ten times farther → flux drops by 100×.
You move 3× farther from a lamp. By what factor does the brightness drop?
A. 3× dimmer
B. 6× dimmer
C. 9× dimmer
D. 27× dimmer
Assume \(F \propto L^a \, d^b\)
| Quantity | Dimension |
|---|---|
| \(F\) (flux) | \([M\,T^{-3}]\) |
| \(L\) (luminosity) | \([M\,L^2\,T^{-3}]\) |
| \(d\) (distance) | \([L]\) |
Match exponents:
\[F \propto \frac{L}{d^2}\]
The \(4\pi\) comes from geometry — DA gives the scaling.
A full sphere subtends \(4\pi\) steradians of solid angle.
Light from an isotropic source spreads evenly over this solid angle. At distance \(d\), the sphere has area \(4\pi d^2\).
So \(F = L/(4\pi d^2)\) simply says: total luminosity ÷ total area of the sphere you’re standing on.
Flux \(F\) (what you measure)
Luminosity \(L\) (what the star emits)
A dim red dwarf nearby can have the same observed flux as a luminous blue giant far away. You cannot determine luminosity from flux alone — you always need distance.
Flux drops as \(1/d^2\), but angular area also drops as \(1/d^2\).
Their ratio — surface brightness — is constant:
\[\frac{F}{\Delta\Omega} = \frac{L/(4\pi d^2)}{\pi R^2/d^2} = \frac{L}{4\pi^2 R^2}\]
This is why galaxy images don’t “fade” at greater distances — they just get smaller. Surface brightness depends only on the source, not distance.
From Distance to Luminosity
The measurement chain
Three rearrangements of one equation:
| Know | Find | Formula |
|---|---|---|
| \(L, d\) | \(F\) | \(F = L/(4\pi d^2)\) |
| \(F, d\) | \(L\) | \(L = 4\pi d^2 F\) |
| \(L, F\) | \(d\) | \(d = \sqrt{L/(4\pi F)}\) |
Given:
Calculate:
\[L_\odot = 4\pi d^2 F\] \[= 4\pi (1.5 \times 10^{13})^2 (1.4 \times 10^6)\] \[= 4\pi \times 3.15 \times 10^{32}\] \[\approx 3.96 \times 10^{33}\,\text{erg s}^{-1}\]
Standard value: \(L_\odot = 3.83 \times 10^{33}\) erg s\(^{-1}\)
Agreement within 4%!
This is how we know the Sun’s luminosity. Every star on the HR diagram uses this same method.
\[d = \frac{1}{p} \implies \frac{\delta d}{d} \approx \frac{\delta p}{p}\]
\[L = 4\pi d^2 F \implies \frac{\delta L}{L} \approx 2\,\frac{\delta d}{d}\]
The complete chain:
10% parallax error → \(\sim 10\)% distance error → \(\sim\)20% luminosity error
Errors double going from distance to luminosity because \(L \propto d^2\).
Gaia’s \(100\times\) parallax improvement → \(100\times\) better luminosity.
Given: \(p = 0.214''\), \(F = 1.1 \times 10^{-7}\) erg cm\(^{-2}\) s\(^{-1}\)
Step 1: \(d = 1/0.214 = 4.67\) pc \(= 1.44 \times 10^{19}\) cm
Step 2: \[L = 4\pi (1.44 \times 10^{19})^2 (1.1 \times 10^{-7})\] \[\approx 2.9 \times 10^{32}\,\text{erg s}^{-1}\]
Step 3: \(L/L_\odot = 2.9 \times 10^{32} / 3.83 \times 10^{33} \approx 0.075\)
This star at \(L \approx 0.08\,L_\odot\) sits on the lower main sequence — a late K or early M dwarf. These small, cool, red stars dominate the Galaxy by number.
A star has parallax \(p = 0.1''\) and flux \(F = 10^{-11}\) erg cm\(^{-2}\) s\(^{-1}\).
Where does your answer land on the HR diagram?
Two stars have identical flux. Star A is at 10 pc, Star B at 100 pc. Which has higher luminosity, and by what factor?
A. Star A, by 10×
B. Star B, by 10×
C. Star A, by 100×
D. Star B, by 100×
Beyond Parallax
Standard candles and the distance ladder
Parallax works out to:
But the Milky Way is \(\sim 30\) kpc across, and Andromeda is \(\sim 770\) kpc away.
How do we measure distances beyond parallax?
If we know a star’s luminosity \(L\), we can measure its flux \(F\) and infer distance:
\[\boxed{d = \sqrt{\frac{L}{4\pi F}}}\]
Objects with known or determinable luminosity are called standard candles.
Cepheid Variables
Type Ia Supernovae
Massive, luminous stars are rare and distant — we need long-reach methods to study them. Standard candles solve this.
Each rung is calibrated by the one below. The entire cosmic distance scale rests on getting nearby parallaxes right — which is why Gaia matters for all of astronomy.
Wrapping Up
| Equation | What it does |
|---|---|
| \(\alpha \approx s/d\) | Angular size ↔︎ true size + distance |
| \(d\,(\text{pc}) = 1/p\,('')\) | Parallax → distance |
| \(F = L/(4\pi d^2)\) | Inverse-square law |
| \(L = 4\pi d^2 F\) | Luminosity from flux + distance |
| \(d = \sqrt{L/(4\pi F)}\) | Standard candle distance |
flowchart LR P["Position shift\n(Observable)"] --> G["Parallax geometry\n(Model)"] G --> D["Distance d\n(Inference)"] F["Flux F\n(Observable)"] --> ISL["Inverse-square law\n(Model)"] D --> ISL ISL --> L["Luminosity L\n(Inference)"] L --> HR["HR Diagram"] style P fill:#dbeafe,stroke:#2563eb style F fill:#dbeafe,stroke:#2563eb style G fill:#fef3c7,stroke:#d97706 style ISL fill:#fef3c7,stroke:#d97706 style D fill:#dcfce7,stroke:#16a34a style L fill:#dcfce7,stroke:#16a34a style HR fill:#f3e8ff,stroke:#9333ea
If you forget everything else from today, remember this:
Distance is the master key.
Measure distance, and luminosity becomes knowable — the first step to understanding any star.
Common questions at this point:
Next time (Lecture 2): Surface Flux & Colors of Stars
Before then:
| Equation | Form | When to use |
|---|---|---|
| Angle conversions | \(1^\circ = 3600''\); \(1' = 60''\) | Angular unit conversion |
| Arcsec ↔︎ radians | \(1\,\text{rad} = 206{,}265''\) | Bridging measurement systems |
| Small-angle | \(\alpha\,(\text{rad}) \approx s/d\) | Angular size, true size, distance |
| Parallax–distance | \(d\,(\text{pc}) = 1/p\,('')\) | Parallax to distance |
| Inverse-square law | \(F = L/(4\pi d^2)\) | Flux, luminosity, distance |
| Luminosity inference | \(L = 4\pi d^2 F\) | Computing luminosity |
| Standard candle | \(d = \sqrt{L/(4\pi F)}\) | Distance from known luminosity |

ASTR 201 • Module 2, Lecture 1