Weighing the Invisible
Show explicit units, and run a sanity check on every result. Worked solutions are released after the homework due date.
Useful constants (CGS):
| Constant | Value |
|---|---|
Useful relations: enclosed mass ; a flat rotation curve has , so ; a central point mass gives ; a circular orbit has .
Conceptual
Problem
⭐⭐ Weighing Sagittarius A* — the inference. Stars at the Galactic center trace small, fast, closed orbits around an invisible point. The enclosed mass comes out near , packed inside the orbit of the closest star.
- (a) State the observable, the model, and the inference for this measurement.
- (b) Explain why the compactness — not the mass alone — is what forces the black-hole interpretation.
- (c) Name one independent observation that supports the same conclusion.
Problem
⭐⭐ Flat does not mean empty. A student claims: “A flat rotation curve means the enclosed mass stops growing past the bright disk — the galaxy is basically empty out there.”
- (a) Use to show what a flat actually implies for .
- (b) Identify the student’s error in one sentence.
- (c) Rising enclosed mass with no rising light tells you what must be present?
Problem
⭐ “Dark” is not “mysterious.” In two or three sentences total:
- (a) State precisely what astronomers mean by calling dark matter “dark.”
- (b) Name the kind of evidence that establishes it, given that no telescope images it directly.
Calculation
Problem
⭐⭐ The luminous-versus-dynamical ledger. A spiral galaxy has a flat rotation speed out to . Its stars and gas (its baryons) sum to .
- (a) Compute the dynamical mass in solar masses.
- (b) Subtract the baryons to get , and form the ratio .
- (c) Inside this radius, is there more dark or baryonic matter — and by roughly what factor?
Problem
⭐⭐ What the Solar System would predict. Suppose a galaxy’s mass were all concentrated at its center, like the Sun in the Solar System. At the orbital speed is .
- (a) For a central point mass, . Predict the speed at .
- (b) The galaxy’s observed speed at is still about (a flat curve). Compare to your prediction.
- (c) What does the gap between the Keplerian prediction and the flat observation reveal?
Problem
⭐⭐ Weigh the black hole with Kepler. The star S2 orbits Sagittarius A* with semi-major axis and period . Treat the orbit as circular.
- (a) Find the orbital speed in .
- (b) Use with to estimate the enclosed mass in solar masses.
- (c) This is the same physics that weighed binary stars in Module 2 — Kepler’s third law. The real S2 orbit is highly elliptical (). Explain why the circular estimate is approximate, and whether using pericenter speed and distance would over- or under-estimate the mass.
Synthesis
Problem
⭐⭐ Two independent witnesses. Dark matter is a convergent inference. Build two distinct observe → model → infer chains for it, drawing on two different lines of evidence (galaxy rotation curves, the Bullet Cluster, cluster gravitational lensing, or the cosmic web).
- (a) Chain 1: observable → model → inference.
- (b) Chain 2: a different observable → model → inference.
- (c) Why is agreement between two independent methods stronger than either alone?
Problem
⭐⭐ A dark engine with visible consequences. A supermassive black hole emits no light from inside its horizon, yet it can reshape a galaxy’s future star formation.
- (a) Explain how an actively accreting black hole (an AGN) injects energy into the galaxy’s gas.
- (b) Connect this to the ecosystem idea from the previous reading: how does AGN feedback resemble stellar feedback?
- (c) Why can a galaxy’s center influence star formation across the whole galaxy?
Problem
⭐⭐⭐ Why the Bullet Cluster is decisive. A skeptic proposes: “There is no dark matter — we just haven’t counted all the ordinary gas, which is most of a cluster’s normal matter.”
- (a) In the Bullet Cluster, where does most of the ordinary matter sit, and how is it located observationally?
- (b) Where does the total gravitating mass sit, and how is it located?
- (c) Explain why the spatial offset between those two defeats the skeptic — what would have to be true for “just more gas” to work, and why the collision rules it out.