Midterm 2 Solutions
Released solutions for Midterm 2
These brief solutions are meant to help you check both your answers and your reasoning. Module 2 emphasizes how observable quantities (parallax, brightness, spectral lines, Doppler shifts) translate into inferred stellar properties (distances, luminosities, temperatures, masses, and eventually a star’s life history).
Answer Key
| Q | Ans | Q | Ans | Q | Ans | Q | Ans | Q | Ans |
|---|---|---|---|---|---|---|---|---|---|
| 1 | A | 6 | D | 11 | A | 16 | A | 21 | D |
| 2 | D | 7 | A | 12 | D | 17 | D | 22 | C |
| 3 | B | 8 | B | 13 | B | 18 | B | 23 | C |
| 4 | B | 9 | D | 14 | C | 19 | C | 24 | A |
| 5 | C | 10 | C | 15 | D | 20 | A | 25 | B |
Brief Solutions
- A. Hot, ionized hydrogen near a young O-type star is an emission nebula (an H II region). The O star’s UV photons ionize the surrounding gas, which then re-emits at characteristic wavelengths.
- D. A 1 \(M_\odot\) star like the Sun is too low-mass to produce a core-collapse supernova or a neutron star/black hole. It ends as a planetary nebula leaving behind a white dwarf.
- B. Only nuclear fusion can sustain the Sun’s luminosity for billions of years. Hydrogen fusing to helium converts a tiny fraction of mass to energy via \(E = mc^2\). Chemical fuels would last \(\sim 10^4\) years, not \(10^9\).
- B. Inverse-square law: \(F \propto 1/d^2\). At three times the distance, brightness is \(1/3^2 = 1/9\).
- C. Once core hydrogen runs out, the inert helium core contracts and heats up, hydrogen-shell burning ignites just outside the core, and the outer envelope expands and cools — the star becomes a red giant.
- D. Stefan-Boltzmann at fixed radius: \(L \propto T^4\). Doubling \(T\) multiplies \(L\) by \(2^4 = 16\).
- A. Only stars more massive than \(\sim 8\,M_\odot\) build inert iron cores and undergo core collapse. A 25 \(M_\odot\) O-type star is the natural Type II progenitor.
- B. Kepler’s third law in solar units: \(M_1 + M_2 = a^3/P^2 = 2^3/2^2 = 2\,M_\odot\).
- D. Wien’s law: \(\lambda_\mathrm{peak} \propto 1/T\). Halving \(T\) (6000 K → 3000 K) doubles \(\lambda_\mathrm{peak}\).
- C. \(R_s = 2GM/c^2 \propto M\). A 10 \(M_\odot\) black hole has a Schwarzschild radius about ten times the Sun’s value, \(\sim 30\) km.
- A. Interstellar dust scatters blue light more strongly than red, and absorbs/dims the through-light. A background star seen through dust appears both dimmer and redder — interstellar reddening.
- D. Mass-luminosity relation: \(L \propto M^{3.5}\). For \(M = 4\,M_\odot\), \(L \approx 4^{3.5} = 4^3 \cdot 4^{0.5} = 64 \cdot 2 = 128\,L_\odot\).
- B. Direct chain: parallax → distance; apparent brightness measured at the telescope; combining with the inverse-square law gives the intrinsic luminosity. Mass and temperature alone cannot give luminosity directly.
- C. Stefan-Boltzmann: \(L = 4\pi R^2 \sigma T^4\). Even at low surface temperature, an enormous radius makes a red giant extremely luminous.
- D. Mass-lifetime: \(t_\mathrm{MS} \propto M^{-2.5}\). For \(M = 4\,M_\odot\), \(t_\mathrm{MS} \approx 10^{10}/4^{2.5} = 10^{10}/32 \approx 3 \times 10^8\) yr ≈ 0.3 Gyr.
- A. Bulk motion of hot plasma rising and cooler plasma sinking is convection, which dominates energy transport in the Sun’s outer convective zone.
- D. When a star leaves the main sequence, its envelope expands and cools while its luminosity rises — it moves into the upper-right (cool, luminous) region of the H-R diagram.
- B. Same apparent brightness, but Star B is 10× farther (parallax is 10× smaller). Inverse-square: 10× farther means 100× more luminous to look the same.
- C. The Chandrasekhar limit (\(\approx 1.4\,M_\odot\)) is the maximum mass an electron-degenerate white dwarf can support. Above it, electron degeneracy pressure cannot resist gravity.
- A. Newton’s law of gravity depends only on mass and distance. Replacing the Sun with a 1 \(M_\odot\) black hole at the same location leaves Earth’s orbit unchanged — the gravitational pull at 1 AU is identical.
- D. The main sequence is a snapshot of stars of different masses simultaneously fusing hydrogen in their cores — not an evolutionary track that a single star follows.
- C. Iron sits at the peak of the binding-energy-per-nucleon curve, so fusing iron absorbs energy rather than releasing it. The core can no longer support itself against gravity, and collapse begins.
- C. Elements heavier than iron are forged in the extreme temperatures and densities of supernova explosions (and neutron-star mergers), through rapid neutron capture (the r-process).
- A. O-type stars are very massive and short-lived (\(\sim\) Myr). If a cluster has G-type main-sequence stars but no surviving O stars, the cluster must be old enough that all its O stars have already evolved off the main sequence.
- B. Neutron-star mergers produce both a chirp of gravitational waves during inspiral and a brilliant electromagnetic counterpart from the colliding matter (kilonova) — first observed together as GW170817 in 2017.